Article ID: 114882
Article Last Modified on 1/18/2007
Function ConsistentDemo ()
Dim rs As Recordset, db As Database
Set db = CurrentDB()
Set rs = db.OpenRecordset("ConsistentDemo", dbOpenDynaset,_
dbInconsistent)
rs.FindFirst "[Customers].[CustomerID]='ALFKI'"
rs.Edit
rs![Customers.CustomerID] = "ALFKJ"
rs.Update
rs.FindFirst "[Customers].[CustomerID]='ALFKJ'"
rs.Edit
rs![Customers.CustomerID] = "ALFKI"
rs.Update
Set rs = db.OpenRecordset("ConsistentDemo", dbOpenDynaset,_
dbConsistent)
rs.FindFirst "[Customers].[CustomerID]='ALFKI'"
rs.Edit
rs![Customers.CustomerID] = "ALFKJ"
rs.Update
rs.FindFirst "[Customers].[CustomerID]='ALFKJ'"
rs.Edit
rs![Customers.CustomerID] = "ALFKI"
rs.Update
rs.Close
db.Close
MsgBox "Test complete."
End Function
In Microsoft Access 2.0:
Function ConsistentDemo ()
Dim rs As Recordset, db As Database
Set db = CurrentDB()
Set rs = db.OpenRecordset("ConsistentDemo", DB_OPEN_DYNASET,_
DB_INCONSISTENT)
rs.FindFirst "[Customers].[Customer ID]='ALFKI'"
rs.Edit
rs![Customers.Customer ID] = "ALFKJ"
rs.Update
rs.FindFirst "[Customers].[Customer ID]='ALFKJ'"
rs.Edit
rs![Customers.Customer ID] = "ALFKI"
rs.Update
Set rs = db.OpenRecordset("ConsistentDemo", DB_OPEN_DYNASET,_
DB_CONSISTENT)
rs.FindFirst "[Customers].[Customer ID]='ALFKI'"
rs.Edit
rs![Customers.Customer ID] = "ALFKJ"
rs.Update
rs.FindFirst "[Customers].[Customer ID]='ALFKJ'"
rs.Edit
rs![Customers.CustomerID] = "ALFKI"
rs.Update
rs.Close
db.Close
MsgBox "Test complete."
End Function
? ConsistentDemo()
? ConsistentDemo()
Additional query words: relationships programming can t
Keywords: kberrmsg kbprb kbprogramming KB114882