KB119083 - XL: MOD() Function Returns #NUM! Error Value

Article ID: 119083

Article Last Modified on 1/19/2007

APPLIES TO

Microsoft Excel 2000 Standard Edition
Microsoft Excel 2002 Standard Edition
Microsoft Excel 97 Standard Edition

This article was previously published under Q119083

For a Microsoft Excel 2001 or Microsoft Excel 98 version of this article, see 119083.

SYMPTOMS

The MOD() function in Microsoft Excel may return a #NUM! error value instead of a valid remainder (modulus).

CAUSE

The MOD() function returns the #NUM! error if the following condition is true:

('divisor' * 134217728) is less than or equal to 'number'

WORKAROUND

If the above condition is true, and the MOD() function returns a #NUM! error, you can use the following formula to calculate the remainder (modulus) of two numbers:

=number-(INT(number/divisor)*divisor)

For example, instead of using this formula

=MOD(J13,K13)

use this formula:

=J13-(INT(J13/K13)*K13)

MORE INFORMATION

In Microsoft Excel, the MOD() function returns the remainder (modulus) of dividing one number by another. The MOD() function accepts two arguments:

   Argument   Definition
   --------------------------------------
   Number     The number being divided
   Divisor    The number being divided by

If you want to calculate the remainder (modulus) of 22 divided by 5, you would use the following formula:

=MOD(22,5)

The result is 2 (22 divided by 5 leaves a remainder of 2).

If the divisor argument, multiplied by 134,217,728 (or 2 raised to the 27th power), is less than or equal to the number argument, the MOD() function returns a #NUM! error value.

Additional query words: 7.00

Keywords: kbprb KB119083