FIX: Explicit Call to Virtual Destructor Corrupts Stack

MORE INFORMATION

~MyClass(2D0340)
i=0, after ptr->~MyClass()
~MyClass(2D134C)
i=1, after ptr->~MyClass()
~MyClass(2D1354)
i=2, after ptr->~MyClass()
~MyClass(2D135C)
i=3, after ptr->~MyClass()
~MyClass(2D1364)
MyClass::operator delete(2D1364)
i=4, after ptr->~MyClass()
~MyClass(2D136C)
MyClass::operator delete(2D136C)
i=5, after ptr->~MyClass()
out of the loop, i=4227241
				

Sample Code

/* Compile options needed: none
*/ 
#include <stdio.h>
class MyClass
{
public:
   void operator delete(void *ptr)
   {
    printf("\nMyClass::operator delete(%lX)", (long)ptr);
   }
   virtual ~MyClass()
   {
    printf("\n~MyClass(%lX)", (long)this);
   }
};
void main(void)
{
   int i;
   MyClass *ptr;
   int j;

   for (i=0; i < 100; i++)
   {
    ptr = new MyClass;
    j = 1;  // Used to put '1' onto the stack

    #ifndef GOOD_CODE
     // This call corrupts the stack, and "accidentally"
     // calls delete()
     ptr->~MyClass();
    #else
     // This call works fine
     ptr->MyClass::~MyClass();
    #endif

    printf("\ni=%d, after ptr->~MyClass()", i);
    fflush(stdout);
   }

   printf("\nout of the loop, i=%d", i);
}