How To Determine the Contents of a Cell in a DBGrid Control

MORE INFORMATION

The DBGrid control allows you to display the contents of a recordset or a table. With this method, you can take the data from a cell in the MouseUp event of the DBGrid control.

This example uses a DBGrid control bound to Data control. The Data control uses the BIBLIO.MDB database for information. In the MouseUp event of the DBGrid control, the column and row positions of the cell are assigned to an integer variable. A bookmark is then set using the row position. Executing the CellValue method on the Columns collection of the DBGrid control determines the contents of the cell. Those contents then appear on a TextBox control.

Sample Code

1. Start Visual Basic. If it is already running, on the File menu, click New Project. Add a DBGrid, TextBox, and a Data control to the Form1 form. Set the following controls to the specified properties:
   
   
   1. Data control DatabaseName property: <path> BIBLIO.MDB RecordSource property: Titles
   2. DBGrid control DataSource property to Data1.
2. Copy the following code sample to the Form1 code window:

         Option Explicit
         Dim igColumn As Integer
         Dim igRow As Integer
         Dim vargBookmark As Variant
   
         Private Sub DBGrid1_MouseUp(Button As Integer, Shift As Integer, _
          X As Single, Y As Single)
            igColumn = DBGrid1.ColContaining(X)   'Set the Cell Column number
            igRow = DBGrid1.RowContaining(Y)      'Set the Cell Row number
   
            vargBookmark = DBGrid1.RowBookmark(igRow) 'Set Bookmark Value
   
            'Show the contents of the cell in a textbox
            Text1.Text = DBGrid1.Columns(igColumn).CellValue(vargBookmark)
   
         End Sub
   
   						

3. On the Run menu, click Start or press the F5 key. Click on a cell and note that the contents is shown in the TextBox.